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10 replies to this topic

#1 TimeSpaceLightForce

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Posted 17 July 2013 - 09:03 PM

The father told his son to make as many non-intersecting triangles with his eight coins.
And for every such triangle (3 centers) counted on the table he will pay 1 coin but take
all coins used to make those triangles . How many coins shall the boy win or lose?


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#2 BMAD

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Posted 17 July 2013 - 09:11 PM

Spoiler for

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#3 TimeSpaceLightForce

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Posted 17 July 2013 - 10:04 PM

Spoiler for

No, the boy only lose a coin for making 7 and only the boy places all his coins


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#4 k-man

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Posted 18 July 2013 - 03:02 PM

Spoiler for I think


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#5 TimeSpaceLightForce

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Posted 18 July 2013 - 06:10 PM

Spoiler for I think

he can do much better than ten


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#6 bonanova

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Posted 18 July 2013 - 06:23 PM

Spoiler for I think

 

This calls for a distinction (is there one?) between non-intersecting and non-overlapping.

Hmm, yeah, I guess there is. :duh:

 

TSLF, care to comment?


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#7 TimeSpaceLightForce

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Posted 18 July 2013 - 06:42 PM

i was thinking that triangle intersection is overlapping of area.. line intersection is overlapping of point


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#8 k-man

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Posted 18 July 2013 - 08:12 PM

Well, if overlapping is not allowed then...

Spoiler for


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#9 TimeSpaceLightForce

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Posted 19 July 2013 - 09:09 AM

Well, if overlapping is not allowed then...

Spoiler for

Spoiler for


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#10 k-man

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Posted 19 July 2013 - 03:36 PM

 

Well, if overlapping is not allowed then...

Spoiler for

Spoiler for

 

 

So, we're solving for flat triangles formed by coins in 3d space?

 

Spoiler for first thought


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