Spoiler for With help

I already found the flaw in my logic. You're right. I'm wrong. <_<

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Guest Message by DevFuse

Started by ash013, Mar 28 2008 05:26 PM

16 replies to this topic

Posted 28 March 2008 - 08:38 PM

Spoiler for With help

I already found the flaw in my logic. You're right. I'm wrong. <_<

Posted 28 March 2008 - 09:05 PM

Ok I got it ... thanx 'jason' and 'grey cells' for the explanation.Into one box there are 30 balls:12 of them are red,13 balls are made from glass and 14 are transperant.If the red balls are not transperant,but 5 of them are made from glass,then how much from the glass balls are transperant?

**Edited by brhan, 28 March 2008 - 09:09 PM.**

Posted 28 March 2008 - 09:53 PM

well 13 - 5 = 8 & 12 - 5 = 6 so there is 8 glass feft and there is 13 + 14 = 27 so there is 3 red balls mad from who knows what and there is 3 red balls left so there must be 3 transparent glass balls

my answer is 3

my answer is 3

Posted 29 March 2008 - 04:58 AM

You are wrong...the answer is definitely 4well 13 - 5 = 8 & 12 - 5 = 6 so there is 8 glass feft and there is 13 + 14 = 27 so there is 3 red balls mad from who knows what and there is 3 red balls left so there must be 3 transparent glass balls

my answer is 3

Posted 29 March 2008 - 06:03 AM

Hi Tink,well 13 - 5 = 8 & 12 - 5 = 6 so there is 8 glass feft and there is 13 + 14 = 27 so there is 3 red balls mad from who knows what and there is 3 red balls left so there must be 3 transparent glass balls

my answer is 3

Check your math in red above. That may help. Or, look at it this way.

Of 12 red balls, none are transparent; 5 are glass.

Of 18 balls that are not red, there are the other 8 glass and all 14 transparent.

Does that help?

*Vidi vici veni.*

Posted 29 March 2008 - 11:13 AM

Yes,the answer is 4.

Posted 31 March 2008 - 10:19 AM

Spoiler for With help

4

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