Jump to content


Welcome to BrainDen.com - Brain Teasers Forum

Welcome to BrainDen.com - Brain Teasers Forum. Like most online communities you must register to post in our community, but don't worry this is a simple free process. To be a part of BrainDen Forums you may create a new account or sign in if you already have an account.
As a member you could start new topics, reply to others, subscribe to topics/forums to get automatic updates, get your own profile and make new friends.

Of course, you can also enjoy our collection of amazing optical illusions and cool math games.

If you like our site, you may support us by simply clicking Google "+1" or Facebook "Like" buttons at the top.
If you have a website, we would appreciate a little link to BrainDen.

Thanks and enjoy the Den :-)
Guest Message by DevFuse
 

Photo
- - - - -

pleasehelp math number wheel puzzle kicking my butt


  • Please log in to reply
12 replies to this topic

#1 michellemybella

michellemybella

    Newbie

  • Members
  • Pip
  • 8 posts

Posted 27 May 2013 - 11:31 PM

I am playing a game on my kindle fire called the quest for snowhill's mystery. Ok well to get the cementery gate open I need to solve this math wheel puzzle, I am not good at math, and the game gives me no number to find. ok so it have 4 moving rings and each has a different number on them, there is a green pointer at the top wich means I guess that's the four stts you use, the puzzle has four moving rings, with numbers on them, what ever is under the pointer gets added up and show up in the middle, hard to explain, but you can get what I am talking about , right? anyway I just want to know how you solve a puzzle like this, it as the numbers so four sets of numbers under the pointer get added up. how do you solve these?thanks and hope you understand been working on this puzzle for over a week and no skip button


  • 0

#2 michellemybella

michellemybella

    Newbie

  • Members
  • Pip
  • 8 posts

Posted 27 May 2013 - 11:50 PM

here is a pic of the puzzle263263_574097622611807_1362889055_n.jpg


  • 0

#3 kingofpain

kingofpain

    Advanced Member

  • Members
  • PipPipPip
  • 354 posts
  • Gender:Male

Posted 28 May 2013 - 08:30 PM

7 + 3 +15+  12  +13  +21 +3   +5 = 79                   19+ 2  +14  +9  +4+  7+    2 +  12= 69

10+6 +  8+  14  +16  +11 +8 +18= 91                    17+ 3+   8+   20 +  9 +18 +8+ 6 = 89

 

Total sum = 328

 

I would say your target for the sum in the middle should be 41.

- This means that under the arrow you should have either only 1 odd number out of 4 or only one even number out of 4.

- Starting clockwise from the green arrow in your picture, 

first circle is           oooeoooo

second circle is     oeeoeoee 

third circle is          eeeeeoee

fourth circle is        .ooeeoeee

 

first and the third circle will line up to sum to an odd number in either 6 positions or 8 positions.

so we need to line up the 2nd and 4th circle so that the sum is even for most part (in all 8 positions is not possible due to 3 consecutive evens in the fourth)

 

Let us check how many evens we get when we shift the 4th ring clockwise

    oeeoeoee 

0: ooeeoeee 4

1: eooeeoee 4

2: eeooeeoe 4

3: eeeooeeo 4

4: oeeeooee 6

5: eoeeeooe 4

6: eeoeeeoo 2

7: oeeoeeeo 6

 

We need options 4 or 7.

Let us try 7 turn of 4th ring clockwise and addit to the second ring

         19   2     14    9     4      7     2   12

          3     8    20    9    18    8      6    17

SUM: 22   10   34    18  22    15    8    29

 

Focus on the odd numbers here. Those will have to correspond with the even numbered sums from rings 1 and 3. Let is pick the 11 from ring 3. It obviously cannot match the 29 since there is no '1' on the first ring and we want the sum to be 41. 12 also cannot match.from the 1st ring since there is no 0 on ring 3.

 

So we try the option of 4 turns clockwise of ring 4. 

         19   2     14    9     4      7     2   12

          9   18     8     6     17    3     8    20

 

SUM: 28   20    22   15   21    10   10  32 

 
Again let us try to match the 11 on the third ring with the 21. this means from the first ring we need a 9 which does not exist. So let us match the 11 with the 15. This means we need the 15 on the first ring which means the rings look as below first to 4th:

           5   7      3    15   12     13   21   3 

         19   2     14    9     4      7     2   12

          9   18     8     6     17    3     8    20

          8   14    16   11    8     18   10    6 

SUM: 41   41   41   41    41    41   41   41   <<<<!!!!!  YAY!

 

Just spin the dials so that the above numbers are lined up as shown and you should be fine. If it does not work, turn ALL the rings together so that a different set of 4 numbers is under the green arrow!


  • 0

#4 BMAD

BMAD

    Senior Member

  • Members
  • PipPipPipPip
  • 1664 posts
  • Gender:Female

Posted 28 May 2013 - 10:24 PM

 

7 + 3 +15+  12  +13  +21 +3   +5 = 79                   19+ 2  +14  +9  +4+  7+    2 +  12= 69

10+6 +  8+  14  +16  +11 +8 +18= 91                    17+ 3+   8+   20 +  9 +18 +8+ 6 = 89

 

Total sum = 328

 

I would say your target for the sum in the middle should be 41.

- This means that under the arrow you should have either only 1 odd number out of 4 or only one even number out of 4.

- Starting clockwise from the green arrow in your picture, 

first circle is           oooeoooo

second circle is     oeeoeoee 

third circle is          eeeeeoee

fourth circle is        .ooeeoeee

 

first and the third circle will line up to sum to an odd number in either 6 positions or 8 positions.

so we need to line up the 2nd and 4th circle so that the sum is even for most part (in all 8 positions is not possible due to 3 consecutive evens in the fourth)

 

Let us check how many evens we get when we shift the 4th ring clockwise

    oeeoeoee 

0: ooeeoeee 4

1: eooeeoee 4

2: eeooeeoe 4

3: eeeooeeo 4

4: oeeeooee 6

5: eoeeeooe 4

6: eeoeeeoo 2

7: oeeoeeeo 6

 

We need options 4 or 7.

Let us try 7 turn of 4th ring clockwise and addit to the second ring

         19   2     14    9     4      7     2   12

          3     8    20    9    18    8      6    17

SUM: 22   10   34    18  22    15    8    29

 

Focus on the odd numbers here. Those will have to correspond with the even numbered sums from rings 1 and 3. Let is pick the 11 from ring 3. It obviously cannot match the 29 since there is no '1' on the first ring and we want the sum to be 41. 12 also cannot match.from the 1st ring since there is no 0 on ring 3.

 

So we try the option of 4 turns clockwise of ring 4. 

         19   2     14    9     4      7     2   12

          9   18     8     6     17    3     8    20

 

SUM: 28   20    22   15   21    10   10  32 

 
Again let us try to match the 11 on the third ring with the 21. this means from the first ring we need a 9 which does not exist. So let us match the 11 with the 15. This means we need the 15 on the first ring which means the rings look as below first to 4th:

           5   7      3    15   12     13   21   3 

         19   2     14    9     4      7     2   12

          9   18     8     6     17    3     8    20

          8   14    16   11    8     18   10    6 

SUM: 41   41   41   41    41    41   41   41   <<<<!!!!!  YAY!

 

Just spin the dials so that the above numbers are lined up as shown and you should be fine. If it does not work, turn ALL the rings together so that a different set of 4 numbers is under the green arrow!

 

nice.  i was trying to make it say 53 :-)


  • 0

#5 michellemybella

michellemybella

    Newbie

  • Members
  • Pip
  • 8 posts

Posted 29 May 2013 - 01:27 AM

I made it 41 and it still did not work, all four rings do move but for some reason it did not work, cant figure out why. made this game is sooooo hard the quest for snowhill'x mystery on my kindle fire, no hint other than it say where did you learn math, no skip. I will keep trying your solution thanks so much for your time, man I hope I can get it, been like over a wek


  • 0

#6 michellemybella

michellemybella

    Newbie

  • Members
  • Pip
  • 8 posts

Posted 29 May 2013 - 01:40 AM

ok did it like you said and did not work still said where did you learn math, ugh....what is the magic number


  • 0

#7 kingofpain

kingofpain

    Advanced Member

  • Members
  • PipPipPip
  • 354 posts
  • Gender:Male

Posted 29 May 2013 - 02:18 AM

Can you send a screenshot of what you are trying? this might help matters!

 

In any case, I was just guessing what the puzzle wanted and actually found after calculations that indeed the 41 approach works... It could be wrong, but I would say a variant is likely to be right...


  • 0

#8 michellemybella

michellemybella

    Newbie

  • Members
  • Pip
  • 8 posts

Posted 29 May 2013 - 10:11 PM

there should be a screen shot under my first post, man this is a hard puzzle


  • 0

#9 michellemybella

michellemybella

    Newbie

  • Members
  • Pip
  • 8 posts

Posted 29 May 2013 - 10:14 PM

it work on the puzzle, not sure what it wants, the green dial on top adds numbers in a row, all four under it, there is no clue as to what you need to find, when you hit the hint button it just says where did you learn math, this game is hard, there is a hint all it says is on screen 64, solve the puzzle to open the gate.


  • 0

#10 BMAD

BMAD

    Senior Member

  • Members
  • PipPipPipPip
  • 1664 posts
  • Gender:Female

Posted 29 May 2013 - 10:48 PM

it work on the puzzle, not sure what it wants, the green dial on top adds numbers in a row, all four under it, there is no clue as to what you need to find, when you hit the hint button it just says where did you learn math, this game is hard, there is a hint all it says is on screen 64, solve the puzzle to open the gate.


After searching another forum, the other site said you need to find a combination somewhere for the door then turn the dials to make the combination of numbers. The center number changes to match the combo you want.

I would try: 53 42 35 33 41

Apparently a lot of people are having trouble finding the combo. No gurantee it will work, just what someone posted on a forum.
  • 0




0 user(s) are reading this topic

0 members, 0 guests, 0 anonymous users