Best Answer bhramarraj, 27 April 2013 - 03:57 PM

There are four sets of conversation:

Mike- Tell me something interesting.

Adam-one of us is always a liar.

Mike-Really?

Eric- Yes. They always lie, but one of us is also always a truth teller.

Mike- Oh, cool, well then …that would mean that Sam is the ‘always liar.’

Sam- Yes, yes I am.

Above tells us:

[1] Adam can't be 'L' if one of them is 'L'. He cold be 'T'.

[2] Eric can't be 'L', if one of them is 'T', but he could be 'T'.

[3] Mike's interpretation from the conversation is not correct, as the conversation which took so far between them could not ascertain that Sam is 'L'. So Mike could be 'L'.

[4] Sam can't be 'L', he is not 'T' also.

Second set of conversation:

Mike-…What? Wait a minute. I thought you were always a liar.

Sam- Yes I am.

Eric-He is.

Mike-He is?

Eric-yes

Sam-yes

Mike-yes?

Adam-no.

Mike-no.

Sam-no.

Above tells us:

[5] Mike could be 'L'.

[6] Sam can't be 'L' or 'T'.

[7] Eric can't be 'T'. Though here he is lying but if one of them was 'T', then he can't be 'L' as he could be 'T' in First set of conversation.

[8] Adam is right here, so he could be 'T'. So he can't be 'L'.

Third set of conversation:

Mike-wait….then does that make Eric the liar?

Eric- Yes

Sam- No

Adam-yes

Mike- What??

Above tells us:

[9] Mike could not be put into any catagoury.

[10] Eric could not be 'T'.

[11] Sam could be speaking truth.

[12] Adam could be telling truth here.

So if one of them is 'L', then it has to be Mike only. And then Adam will be 'T'.