A Car passes as many Lamptposts in 2 minutes as its speed is in miles per hour. What is the distance between the Lamposts in feet?
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Posted 26 April 2013 - 08:43 AM
Edit - check this. speed = x mph = 5280x fph = 5280x/60 fpm = 88x fpm. Thus, in 2 minutes the car travels 176x feet. We are told that in 2 minutes he passes x lamp posts. Thus there is 176 feet per lamp post.
30 lamps = 1 mile = 5280 feet
1 lamp = 176 feet.
That is the lamppost spacing.
That is the spacing.
Edit - check this.
speed = x mph = 5280x fph = 5280x/60 fpm = 88x fpm.
Thus, in 2 minutes the car travels 176x feet.
We are told that in 2 minutes he passes x lamp posts.
Thus there is 176 feet per lamp post.
Vidi vici veni.
Posted 04 May 2013 - 05:22 PM
I hope this is the reasonable answer.
Posted 06 May 2013 - 07:33 AM
Vidi vici veni.
Posted 06 May 2013 - 11:37 AM
bhramarraj, we differ by an interpretation of OP, which is ambiguous.
If "2 minutes" means "every 2 minutes" or "a particular 2-minute interval" the answer could be what jordge and I posted or your answer or anything in between. That is, in the second case the first pole is passed (sometime) in the first minute and the second pole is passed (sometime) during the second minute. That would permit your answer if pole 1 happened at the beginning of minute 1, and the second pole happened at the end of minute 2.
Or am I missing something?
So, is John Wilson still around to clarify?
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