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#1 BMAD

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Posted 08 April 2013 - 11:23 PM

Find pairs of positive integers where 2a = 3b + 5.  Prove that you have found them all.


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#2 bonanova

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Posted 09 April 2013 - 11:23 AM

Spoiler for for starters


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The greatest challenge to any thinker is stating the problem in a way that will allow a solution.
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#3 BMAD

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Posted 09 April 2013 - 02:10 PM

Bonanova,

Do you mean 2^2 = 3^2 + 5 ?
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#4 TimeSpaceLightForce

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Posted 09 April 2013 - 03:03 PM

Spoiler for 2


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#5 BMAD

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Posted 09 April 2013 - 06:11 PM

This is a good start.

Spoiler for 2


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#6 bonanova

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Posted 09 April 2013 - 07:50 PM

Bonanova,
Do you mean 2^2 = 3^2 + 5 ?


I plead drowsiness. I read the puzzle incorrectly. Minus 5 obviously.
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The greatest challenge to any thinker is stating the problem in a way that will allow a solution.
- Bertrand Russell

#7 BMAD

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Posted 05 May 2013 - 01:51 AM

Spoiler for hint, to get you started

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#8 TimeSpaceLightForce

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Posted 09 May 2013 - 05:34 PM

I cant find the those elusive evens ..using excel i formulate the 2 expressions with 1-300 exponents ,

add both on a column , sort ascending and check for equal consecutive..


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#9 BMAD

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Posted 09 May 2013 - 09:16 PM

Spoiler for hint 2

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#10 BMAD

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Posted 11 May 2013 - 07:06 PM

Spoiler for hint 3

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