1 2 3 4 5 6 7 8 9
Arrange these numbers into two separate groups so that they add up to same total.
Note : you cant turn 9 upside down and make it 6
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Best Answer vinay.singh84, 20 March 2013 - 05:19 PM
(sum=27)
12 6 9 | 3 4 5 7 8
12 4 5 6 | 3 7 8 9
3 4 5 6 9 | 12 7 8
...
(sum=36)
31 5 | 2 4 6 7 8 9
...
(sum=45)
31 5 9 | 24 6 7 8
...
A better question would be "How many different pairs of groups (with the same sum) can be formed?"
Posted 19 March 2013 - 09:43 AM
1 2 3 4 5 6 7 8 9
Arrange these numbers into two separate groups so that they add up to same total.
Note : you cant turn 9 upside down and make it 6
Posted 19 March 2013 - 10:26 AM
1 2 3 4 5 6 7 8 9
Arrange these numbers into two separate groups so that they add up to same total.
Note : you cant turn 9 upside down and make it 6
1 2 3 4 5 6 and 6 7 8 should do it. Or turn the 6 into 9, increasing the total by 3 to 48. 1 2 3 4 5 9 and 7 8 9 do it for that case.
Numbers 1-9 total 45, which can't be evenly split.
Making the 9 a 6 reduces that total by 3 to 42.
So we need two groups that each total 21.
Posted 19 March 2013 - 10:30 AM
Posted 19 March 2013 - 10:31 AM
1 2 3 4 5 6 7 8 9
Arrange these numbers into two separate groups so that they add up to same total.
Note : you cant turn 9 upside down and make it 6
Spoiler for Looks likeYou have to turn the 9 into a six.
Numbers 1-9 total 45, which can't be evenly split.
Making the 9 a 6 reduces that total by 3 to 42.
So we need two groups that each total 21.
1 2 3 4 5 6 and 6 7 8 should do it.
Or turn the 6 into 9, increasing the total by 3 to 48.
1 2 3 4 5 9 and 7 8 9 do it for that case.
this is what even i think how can you split 45 into two equal parts...P.S- he noted that we cant use 9 as 6... ![]()
Posted 19 March 2013 - 10:44 AM
1 2 3 4 5 6 7 8 9
Arrange these numbers into two separate groups so that they add up to same total.
Note : you cant turn 9 upside down and make it 6
Spoiler for Looks likeYou have to turn the 9 into a six.
Numbers 1-9 total 45, which can't be evenly split.
Making the 9 a 6 reduces that total by 3 to 42.
So we need two groups that each total 21.
1 2 3 4 5 6 and 6 7 8 should do it.
Or turn the 6 into 9, increasing the total by 3 to 48.
1 2 3 4 5 9 and 7 8 9 do it for that case.
this is what even i think how can you split 45 into two equal parts...P.S- he noted that we cant use 9 as 6...
Ah, I misread that. Good catch.
He did not say that you could not turn the 6 into a 9.
Posted 19 March 2013 - 10:48 AM
Posted 20 March 2013 - 09:36 AM
1 2 3 4 5 6 7 8 9
Arrange these numbers into two separate groups so that they add up to same total.
Note : you cant turn 9 upside down and make it 6
Spoiler for Looks likeYou have to turn the 9 into a six.
Numbers 1-9 total 45, which can't be evenly split.
Making the 9 a 6 reduces that total by 3 to 42.
So we need two groups that each total 21.
1 2 3 4 5 6 and 6 7 8 should do it.
Or turn the 6 into 9, increasing the total by 3 to 48.
1 2 3 4 5 9 and 7 8 9 do it for that case.
There is one solution in which you don't have to turn 6 into 9 or 9 into 6
The one who will give me that answer will be marked as best answer
So common guys give it a try
Posted 20 March 2013 - 09:41 AM
Spoiler for here's maybe oneGroup 1: 18,9,3,6
Group 2: 27, 4,5
both add up to 36
Good can you find one more
to get marked as best answer because there is one more competitor.
Edited by Utkrisht123, 20 March 2013 - 09:43 AM.
Posted 20 March 2013 - 09:43 AM
Spoiler for possiblyGroup-one: 83,7,4,5
Group-two: 91,2,6
Good can you find one more
to get marked as best answer because there is one more competitor.
First one to give one more solution will be marked best answer
Edited by Utkrisht123, 20 March 2013 - 09:47 AM.
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