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Best Answer austinm, 18 March 2013 - 03:50 PM

Spoiler for this many:

Spoiler for how?

 

This question gets much more interesting if we go, say, 1.5 block-lengths outside of the original footprint--shape of tower differs dramatically.

Go to the full post


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#1 bonanova

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Posted 18 March 2013 - 02:53 PM

You are stacking children's building blocks on a level table.

They are perfect, identical cubes, evenly weighted, and you're

not fastening them together in any way.

 

The stack is not very straight.

In fact at one point you notice the topmost block (viewed from

overhead) is completely outside the footprint of the bottom block.

 

What is the minimum number of blocks in your tower?

Or is that even possible?


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The greatest challenge to any thinker is stating the problem in a way that will allow a solution.
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#2 austinm

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Posted 18 March 2013 - 03:50 PM   Best Answer

Spoiler for this many:

Spoiler for how?

 

This question gets much more interesting if we go, say, 1.5 block-lengths outside of the original footprint--shape of tower differs dramatically.


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#3 bonanova

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Posted 18 March 2013 - 04:36 PM

Spoiler for this many:

Spoiler for how?

 

This question gets much more interesting if we go, say, 1.5 block-lengths outside of the original footprint--shape of tower differs dramatically.

 

The balance is precarious at the 1-2 edge and the 4-5 edge, but some of the 1/24 can be spent to make them stable.

If the middle blocks are rotated, hmmm... might not matter.

Nice job.


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The greatest challenge to any thinker is stating the problem in a way that will allow a solution.
- Bertrand Russell

#4 austinm

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Posted 18 March 2013 - 04:58 PM

I can make the separation-from-original-footprint greater than 1/24 (and spend an arbitrarily-small portion of that gain to ensure it's not precarious)--can you?

Spoiler for the separation I get


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