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Posted 28 February 2013 - 06:26 AM

Two ladders are placed cross-wise in an alley to form a lopsided X-shape.  The walls of the alley are not vertical, but are parallel to each other.  The ground is flat and horizontal.  The bottom of each ladder is placed against the opposite wall.  The top of the longer ladder touches the alley wall 18 feet vertically higher than the top of where the shorter ladder touches the opposite wall, which in turn is 6 feet vertically higher than the intersection of the two ladders.  How high vertically above the ground is that intersection?

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### #2 k-man

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Posted 28 February 2013 - 04:17 PM   Best Answer

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### #3 tammie

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Posted 28 February 2013 - 05:35 PM

12 ft?  not entirely sure this is right. but i'm thinking that the intersection on the smaller ladder would be 2/3 of the ladders length. and the shorter ladderwould meet the top of the wall at the halfway point of the length of the point that the tall ladders top meets the walls. 18ft from the top of the tall to the top of the short and 18 from the top of the short to the ground  minus the 6ft down to the intersection =12 ft. from the ground? and i think that my logic only makes sense in my own head.

Edited by tammie, 28 February 2013 - 05:44 PM.

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### #4 k-man

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Posted 28 February 2013 - 05:47 PM

Welcome to the Den, tammie!

Please use spoilers when posting answers. To add a spoiler to your reply you can use the "S" button above the reply box. If the button doesn't work or if you're posting from a mobile device you can enclose the text you want hidden in the spoiler tags:

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I put a space in the first tag, so that it doesn't get recognized. Without the space it will turn into this:

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### #5 tammie

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Posted 05 March 2013 - 07:13 PM

Spoiler for thanks for the welcome and the info

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