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### #1

Posted 26 March 2008 - 01:59 AM

2/100, 4/10000, 8/10^6, 16/10^8, 32/10^10, ...

Yeah....its a simple geometric series....but it is kinda interesting when you multiply each term by 7 and see what the sum is equal to.

### #2

Posted 26 March 2008 - 02:16 AM

2

^{n}/10

^{2n}

### #3

Posted 26 March 2008 - 02:20 AM

### #4

Posted 26 March 2008 - 02:39 AM

from what I can tell the nth term is

2^{n}/10^{2n}

That's right, though it can be simplified to a simple power of a fraction.

### #5

Posted 26 March 2008 - 05:29 AM

What is the sum of this series equal to in the limit?

2/100, 4/10000, 8/10^6, 16/10^8, 32/10^10, ...

Yeah....its a simple geometric series....but it is kinda interesting when you multiply each term by 7 and see what the sum is equal to.

*The greatest challenge to any thinker is stating the problem in a way that will allow a solution.*

- Bertrand Russell

### #6

Posted 26 March 2008 - 07:54 AM

### #7

Posted 26 March 2008 - 01:49 PM

So, echo ... guess you looked the formula up after all.Spoiler for result

*The greatest challenge to any thinker is stating the problem in a way that will allow a solution.*

- Bertrand Russell

### #8

Posted 26 March 2008 - 08:12 PM

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