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Lethal Solution


Best Answer CaptainEd, 17 December 2012 - 07:53 PM

Spoiler for OK, a=a solution=solution with=with no=no pouring=pouring at=at all'=all
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#11 TimeSpaceLightForce

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Posted 17 December 2012 - 06:32 PM

I totally agree--Badhri's principle is much more practical in terms of masses.

..too many moves and uncertainties


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#12 famous1304

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Posted 17 December 2012 - 06:35 PM

If using the LCD screen, I would put all 4 on the scale, and remove one until one took off more weight than the others.  only using the scale once.  Or you could go the opposite route, and you would have to put them all on the scale one at a time as to not spill.  So just watch the weights as you put a new cup on and you would know which one had the poison.


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#13 CaptainEd

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Posted 17 December 2012 - 06:36 PM

Spoiler for Badhri's principle is the winner, details need cleanup

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#14 TimeSpaceLightForce

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Posted 17 December 2012 - 06:43 PM

If using the LCD screen, I would put all 4 on the scale, and remove one until one took off more weight than the others.  only using the scale once.  Or you could go the opposite route, and you would have to put them all on the scale one at a time as to not spill.  So just watch the weights as you put a new cup on and you would know which one had the poison.

Your solution is right unless making the machine do its job means using it
(in that case reading weight trice). It is resting if nothing is on it. If there is

a reading already using once means having a new reading..

Use the scale tray if you would like take them  off  or place them on the scale


Edited by TimeSpaceLightForce, 17 December 2012 - 06:45 PM.

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#15 CaptainEd

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Posted 17 December 2012 - 07:53 PM   Best Answer

Spoiler for OK, a=a solution=solution with=with no=no pouring=pouring at=at all'=all

Edited by CaptainEd, 17 December 2012 - 08:02 PM.

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#16 TimeSpaceLightForce

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Posted 18 December 2012 - 10:01 AM

Spoiler for Badhri's principle is the winner, details need cleanup

if you have estimated half a glass and it  weighs more than half the water weight, the additional weight can be water or poison's..thats why the volume must be precisely measured as done here..still that is troublesome.. the glass weight shall be considered too in that case


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#17 TimeSpaceLightForce

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Posted 18 December 2012 - 10:06 AM

I'm not sure I would accept this challange. But if I had to , place two glasses on scale. Either these two, or the other two weigh 2A+x. We now know that the poison is one of of the two heavier pairs. Now the hard part : drink one of these glasses. If you don't die, you know the other glass is poison. If you die, you go to your grave knowing you were also correct

This is one solution if you have a goldfish in the bowl


Edited by TimeSpaceLightForce, 18 December 2012 - 10:09 AM.

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#18 TimeSpaceLightForce

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Posted 18 December 2012 - 06:11 PM

Spoiler for OK, a=a solution=solution with=with no=no pouring=pouring at=at all'=all

I can not say no to this one  CaptainEd it is so resourceful and using mechanics is cool..using knife and bench and plank.

Spoiler for


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#19 CaptainEd

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Posted 18 December 2012 - 06:24 PM

I can not say no to this one  CaptainEd it is so resourceful and using mechanics is cool..using knife and bench and plank.

Spoiler for

Glad you like it, but now, in the absence of a poison scanner dog, what in the world was the solution you were envisioning?


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#20 TimeSpaceLightForce

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Posted 18 December 2012 - 07:05 PM

Spoiler for Lethal Solution

Warning: DO NOT try this at home !

 

 

 


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