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Guest Message by DevFuse
 

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another very long task


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12 replies to this topic

#11 phil1882

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Posted 16 August 2012 - 08:09 AM

so i guess the next logical question is this, if every irrational number is countably infinite in it representation, can you represent all irrational numbers in a countably infinite way? that is, we know we can form any individual irrational number with a series of 1's and 0's. there is no individual irrational number we can't form this way. now imagine we have a countably infinite number of people flipping coins. which irrational number won't be hit?
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#12 EventHorizon

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Posted 16 August 2012 - 11:40 AM

so i guess the next logical question is this, if every irrational number is countably infinite in it representation, can you represent all irrational numbers in a countably infinite way? that is, we know we can form any individual irrational number with a series of 1's and 0's. there is no individual irrational number we can't form this way. now imagine we have a countably infinite number of people flipping coins. which irrational number won't be hit?

Spoiler for Answer

Edited by EventHorizon, 16 August 2012 - 08:17 PM.

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#13 bonanova

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Posted 16 August 2012 - 04:55 PM

That was a reply to your question. Is the answer the obvious "almost all" of them?
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The greatest challenge to any thinker is stating the problem in a way that will allow a solution.
- Bertrand Russell




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