If 2 is true, 1 is false. (statement 2)

If 2 is false, 1 cannot be true (statement 2)

So 1 is false. (previous two lines)

Since 1 is false, so are 9 and 10 (statement 1)

6 is true (assuming 6 is false says 6 is the last true statement = contradiction)

If 2 is false, then 3 must be true (if 1,2,and 3 are false, there are 3 consecutive false, so 3 is true =contradiction), and if 3 is false, 2 must be true. So how about we assume 3 is false and see what happens.

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Assume 3 is false

2 is true since if 1,2,and 3 are false then 3 is true (statement 3)

8 is true since if 8,9,and 10 are false then 3 is true (statement 3)

5 is false since 8 is true and sum of numbers from 1 to 8 is 36, if 5 was true 8 would be false (percentage would need to be simultaneously greater than 40 and less than 36).

4 is true (statement 3)

x has a factor of 6. (statement 4)

7 is true (10 is false)

The true statements are 2,4,6,7,8. So x=50. (50% are true and statement 8)

But 50 does not have a factor of 6

Contradiction!

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3 is true (previous block)

8 is false (the three consecutive false statements (from 3) must include 8 now)

7 is true (statement 6)

5 is false (since 7 is true and 6 and 7 are factors of x, but adding up 1 through 7 is less than 42)

2 and 4 are true. (There needs to be 3 consecutive true statements or 10 would need to be true)

5 is a factor of x (statement 4)

2,3,4,6 and 7 are factors of x (statement 7)

Since 2,3,4,5,6, and 7 are factors of x, x is a multiple of 420. (least common multiple)

The factors of 420 (besides 1 and 420), are:

2, 3, 4, 5, 6, 7, 10, 12, 14, 15, 20, 21, 28, 30, 35, 42, 60, 70, 84, 105, 140, and 210.

There are 22 of them.

Adding the numbers of the true statements also gives 22.

If x was any multiple of 420 other than 420 itself, it would make statement 9 true by having too many factors.

x=420

Looks like I agree with Molly Mae