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not so easy Math Problem
Posted 07 June 2012 - 02:03 PM
Going uphill, it goes at 56 mph.
Going downhill, it goes at 72 mph.
On level ground, it goes at 63 mph.
If it takes 4 hours to travel from A to B, and 5 hours to come back,
what is the distance between A and B?
Posted 07 June 2012 - 02:51 PM
Edited by kevink2, 07 June 2012 - 02:52 PM.
Posted 07 June 2012 - 02:55 PM
Edited by Potok, 07 June 2012 - 02:57 PM.
Posted 07 June 2012 - 03:10 PM
Spoiler for My answer
turned out to be so easy I guess. well done
Same answer here, is ofc correct.Spoiler for the formula for the downhill
Posted 07 June 2012 - 04:03 PM
Edited by CaptainEd, 07 June 2012 - 04:10 PM.
Posted 07 June 2012 - 04:22 PM
Posted 07 June 2012 - 10:02 PM
Oops, you're right, I got it backward.
So in your solution A is lower (compared to sea level) than B and you travel from A to B mostly uphill ? But the path from A to B is (timewise) shorter than from B to A.
Posted 08 June 2012 - 07:56 AM
x/63 + y/56= 5
x = 31.5 Mi ; net ground level distance.
y = 252 Mi ; net inclined distance
Total x + y = 283.5 Mi.
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