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Rabbit Hutch


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#21 Kro-G

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Posted 27 November 2007 - 09:37 PM

Little house for 6 rabbits (just 12 matches)

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#22 mustavarest

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Posted 10 December 2007 - 09:15 PM

I had assumed that the requirement was that the floor area of each new area should be the same as previouslly. It's a long time since I studied geometry but I think the solution given does this whereas most (if not all) of the alternatives offered do not!
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#23 Kro-G

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Posted 15 December 2007 - 08:14 PM

The solution of author is wrong.
He wrote the same area?

the cell area on the first picture is P=1/2a*a where a is lenght of match for ex=10
so area of 1 cell will be 50

on his picture we have equila teraltriangle so P=(a*a*square root(3))/4 where a is lenght of match for ex=10
so are of 1 cell will be 43,30

on my solution
right-angled triangle so P=a*a/2 where a is lenght of match for ex=10

so area of 1 cell will be 50
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#24 rookie1ja

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Posted 15 December 2007 - 11:09 PM

The solution of author is wrong.
He wrote the same area?

the cell area on the first picture is P=1/2a*a where a is lenght of match for ex=10
so area of 1 cell will be 50

on his picture we have equila teraltriangle so P=(a*a*square root(3))/4 where a is lenght of match for ex=10
so are of 1 cell will be 43,30

on my solution
right-angled triangle so P=a*a/2 where a is lenght of match for ex=10

so area of 1 cell will be 50


so you claim that my solution:
1. does not offer the same (equally big) area for 6 rabbits
2. made of 12 matchsticks

???

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#25 Kro-G

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Posted 16 December 2007 - 08:45 PM

Yes If it is in 2d your solutions is wrong.
Maybe rabbits will have enough space ;-) but it will be less than on the begining.
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#26 Kro-G

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Posted 16 December 2007 - 08:49 PM

Look also on my solution with scales it is alternatve to your solution.
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#27 rookie1ja

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Posted 16 December 2007 - 08:55 PM

Yes If it is in 2d your solutions is wrong.
Maybe rabbits will have enough space ;-) but it will be less than on the begining.


I have not mentioned anything about enough space ... less does not mean not enough ... btw, have you seen a rabbit that would fit into your or my image?

ps: have you noticed that your solution is not made of matchsticks of the same size? check the hypotenuses
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#28 Kro-G

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Posted 16 December 2007 - 09:42 PM

If you are so smart give my solution of this problem triangle A1A2A3 is make one plane A and is formated on platen plane Z, triangle B1B2B3 is make the second plane B and is formated on plated plane x , plane Z is perpendicular to plane X finde the cuting edge of Tr A1A2A3 & B1B2B3 (all is in 3d of course)

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#29 rookie1ja

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Posted 16 December 2007 - 09:44 PM

If you are so smart give my solution of this problem triangle A1A2A3 is make one plane A and is formated on platen plane Z, triangle B1B2B3 is make the second plane B and is formated on plated plane x , plane Z is perpendicular to plane X finde the cuting edge of Tr A1A2A3 & B1B2B3 (all is in 3d of course)


good luck with your homework
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#30 Kro-G

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Posted 16 December 2007 - 09:51 PM

This is so easy dont think just try ;-)
I know the solution and I will give it in next week bye.
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