Spoiler for but
Edit: typo.
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Crossing the River
#21
Posted 15 January 2012 - 04:49 PM
#22
Posted 15 January 2012 - 07:32 PM
Ok guys I could get the solution with a spend of $32
Consider the families as denoted by their first letters as follows : Side1 (f, m, s, d, b) and Side2 (f', m', s', d' b')
Here is the sequence to follow :
1) s,d,b moves from Side1 to Side 2
Cost incurred = $6
2) s', d', b' moves from Side2 to Side1
Cost incurred = $6
3) f, m, b' moves from Side1 to Side 2
Cost incurred = $10
4) f', m' , b' moves from Side2 to Side1
Cost incurred = $10
Total cost incurred = $ 6+6+10+10 = $32
#23
Posted 15 January 2012 - 08:00 PM
Spoiler for how this one could work
#24
Posted 16 January 2012 - 02:25 AM
Spoiler for ... and
#25
Posted 16 January 2012 - 06:59 AM
#26
Posted 16 January 2012 - 09:18 AM
sorry, the baby can only go with a member of HIS familySpoiler for solution
#27
Posted 16 January 2012 - 09:29 AM
#28
Posted 16 January 2012 - 11:56 AM
#29
Posted 16 January 2012 - 01:33 PM
#30
Posted 16 January 2012 - 02:02 PM
can i ask one thing?? is there a limit in max no. of persons that can travel in the boat at a time mentioned?? only the minimum is mentioned... so one family can go together. costs only 15... hi hi.. prob solved
But from wolgang's post (post #16), he says ----
The total sum is 33$ for the both two families( i.e.the money ,33$,are devided between them,...somehow...)
The boats driver must be always on his boat.
The boat can take only four persons each time( no more and no less),i.e.the boat driver and exactly three persons.
Each baby must be accompanied with ,at least,one person of his own family.
Edited by thoughtfulfellow, 16 January 2012 - 02:03 PM.
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