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Guest Message by DevFuse

Crossing the River

39 replies to this topic

#11 ak4su

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Posted 14 January 2012 - 07:30 PM

three persons on board

What do you think he means
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#12 Smith

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Posted 14 January 2012 - 08:47 PM

In that case, try this solution:

Spoiler for Yet another attempt

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#13 krisha.patel0110

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Posted 14 January 2012 - 10:52 PM

First off, does the driver have to be in the boat when it crosses and does the boat hold 3 or 4 ppl?
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#14 perry1843

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Posted 15 January 2012 - 10:15 AM

Well, I'm sure that there is more to this than is posted, but..

Based on the given information and the way it is stated, I get the impression the Boat Driver has a 3 person minimum for making the trip worth his while. After all, I don't see where it says that 3 is the MAX that he will/can take? That being said, would not each family board the boat on their respective sides, pay the driver the \$15 for his services and disembark on the opposite sides of the river, each with \$1.50 in hand?

Please let me know what I have missed in the puzzle, because it appears pretty straight forward.
Thanks!
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#15 thoughtfulfellow

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Posted 15 January 2012 - 10:21 AM

If it is the boat driver PLUS exactly three passengers, the solution is too easy and costs way less than the \$66 total available:

Spoiler for Driver Plus 3 Passengers Solution

Well, given thoughtfulfellow's response, I now must assume that wolfgang meant that there was a GRAND TOTAL of \$33 between the two families' funds. Therefore, my solutions cost \$38 and \$34, respectively. That also means that thoughtfulfellow spent \$4 less on his "Driver + 3 Passengers" solution (I'd like to see it). Oh, well. Back to the drawing board.

(and, post-posting, I see mewminator's comment to the same effect. Thank you, mewminator.)

If you double check your first solution third and forth trips, the steps I changed to red, F M & D only total a cost of \$11 so your solution is mine for achieving \$34. I did trips in slightly different order but with same results

Edited by thoughtfulfellow, 15 January 2012 - 10:22 AM.

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#16 wolfgang

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Posted 15 January 2012 - 12:06 PM

The total sum is 33\$ for the both two families( i.e.the money ,33\$,are devided between them,...somehow...)
The boats driver must be always on his boat.
The boat can take only four persons each time( no more and no less),i.e.the boat driver and exactly three persons.
Each baby must be accompanied with ,at least,one person of his own family.

Edited by wolfgang, 15 January 2012 - 12:13 PM.

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#17 avaidhyan

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Posted 15 January 2012 - 12:30 PM

Ok guys I could get the solution with a spend of \$32
Consider the families as denoted by their first letters as follows : Side1 (f, m, s, d, b) and Side2 (f', m', s', d' b')

Here is the sequence to follow :
1) s,d,b moves from Side1 to Side 2
Cost incurred = \$6

2) s', d', b' moves from Side2 to Side1
Cost incurred = \$6

3) f, m, b' moves from Side1 to Side 2
Cost incurred = \$10

4) f', m' , b' moves from Side2 to Side1
Cost incurred = \$10

Total cost incurred = \$ 6+6+10+10 = \$32
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#18 ak4su

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Posted 15 January 2012 - 12:36 PM

The problem is only with the third one, baby has to be accompanied with a family member.
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#19 thoughtfulfellow

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Posted 15 January 2012 - 01:40 PM

Some inconclusive analysis
Spoiler for What I see

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#20 Morningstar

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Posted 15 January 2012 - 04:30 PM

Some inconclusive analysis

Spoiler for What I see

Spoiler for but

Edit: typo.

Edited by Morningstar, 15 January 2012 - 04:31 PM.

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The cake is a lie.

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