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# Crossing the River

39 replies to this topic

### #1 wolfgang

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Posted 14 January 2012 - 02:17 PM

Two families(1 and 2),each consists of 5 persons(Father,Mother, Son,Daughter,and Baby).
Family 1 is at the right side of the river®,and Family 2 at the left side of the river(L).
They want to change places.
There is only one boat with its driver,the boat will not cross the river unless there are three persons on board(baby is one person).
Each father should pay 5\$ for each single cross, each mother 4\$,each son 3\$,each daughter 2\$,and each baby 1\$.
Both families have a total of 33\$.
Any baby should be accompanied with any one of his family.
How can they change their places using that amount of money?
they should use the boat only.
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### #2 thoughtfulfellow

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Posted 14 January 2012 - 04:57 PM

You are going to make me lose sleep on this one! My first try got the total to \$34. Will work on it more. I am assuming that you mean the driver plus exactly three passengers and, since the baby must travel with a family member, that it also must have a family member on the side with it.
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### #3 Smith

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Posted 14 January 2012 - 06:17 PM

If it is the boat driver PLUS exactly three passengers, the solution is too easy and costs way less than the \$66 total available:
Spoiler for Driver Plus 3 Passengers Solution

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### #4 Smith

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Posted 14 January 2012 - 06:31 PM

If the boat driver is included in the three total passengers on each boat trip, the solution still costs way less than the \$66 total available:
Spoiler for Driver plus 2 Passengers Solution

Edited by Smith, 14 January 2012 - 06:32 PM.

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### #5 mewminator

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Posted 14 January 2012 - 06:31 PM

Spoiler for maybe

I've yet to make that solution
@smith

Both families have a total of 33\$.

not each family has 33\$, 33\$ is the maximum both families combined can pay.

Edited by mewminator, 14 January 2012 - 06:40 PM.

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### #6 Smith

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Posted 14 January 2012 - 06:38 PM

Well, given thoughtfulfellow's response, I now must assume that wolfgang meant that there was a GRAND TOTAL of \$33 between the two families' funds. Therefore, my solutions cost \$38 and \$34, respectively. That also means that thoughtfulfellow spent \$4 less on his "Driver + 3 Passengers" solution (I'd like to see it). Oh, well. Back to the drawing board.

(and, post-posting, I see mewminator's comment to the same effect. Thank you, mewminator.)

Edited by Smith, 14 January 2012 - 06:46 PM.

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### #7 Morningstar

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Posted 14 January 2012 - 06:48 PM

Wait...is it a combined total of \$33 or \$66?
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The cake is a lie.

### #8 mewminator

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Posted 14 January 2012 - 06:51 PM

Spoiler for reason of imposibility

I missed something
I guess I need more than maths to solve this one
@smith 3 passengers and the money is payed to the driver
@moningstar \$33 is the maximum possible you can pay, otherwise ther would be no riddle

Edited by mewminator, 14 January 2012 - 06:54 PM.

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### #9 ak4su

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Posted 14 January 2012 - 06:58 PM

Spoiler for Maybe hint

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### #10 Smith

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Posted 14 January 2012 - 07:26 PM

In light of ak4su's comment, I think a clarification is in order...
Spoiler for Clarifying Question which holds a minor clue, so look at your own risk!

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