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Pirates and Laptops


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#11 Morningstar

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Posted 15 January 2012 - 04:25 PM

Kudos to SeaCalMaster!
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The cake is a lie.

#12 petar

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Posted 03 May 2013 - 09:33 PM

I think the solution is: only 3 pirates left, the elder one will get 0 laptops, because his priority is not to die over having Laptop, then he propose all the 100 laptops to the second pirate and 0 to the third, that way he gets the most votes and doesn't die. This could not apply for 4 or more because they would have to split the laptops and if they split them then they would prefer to kill the first pirate. What do you Think?


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#13 petar

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Posted 03 May 2013 - 11:29 PM

I think the solution is: only 3 pirates left, the elder one will get 0 laptops, because his priority is not to die over having Laptop, then he propose all the 100 laptops to the second pirate and 0 to the third, that way he gets the most votes and doesn't die. This could not apply for 4 or more because they would have to split the laptops and if they split them then they would prefer to kill the first pirate. What do you Think?

Actually I think 99 - 0 - 1 would be the solition


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