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Posted 21 March 2008 - 09:06 PM
They are trying to divide up the treasure in a way that is fair, so they go from oldest to youngest, offering proposals. The oldest pirate will go first and propose how to divide up the treasure, and the others will vote on it. If half or more of the total pirates alive vote against the proposal, the oldest will be killed, and the second oldest will then come up with a proposal that the others will vote on.
If more than half votes in favor of the proposal, they will divide up the treasure according to the proposal, and go their separate ways.
Assuming all of the pirates are extremely smart, and they all want to live, how will the treasure be divided up?
Posted 21 March 2008 - 09:10 PM
Posted 21 March 2008 - 09:12 PM
Also, please put your response in a spoiler... Kind of late now since it was first response... Didn't think I needed to say that.
Edited by Noct, 21 March 2008 - 09:15 PM.
Posted 21 March 2008 - 09:54 PM
Edited by itachi-san, 21 March 2008 - 09:56 PM.
Posted 21 March 2008 - 09:58 PM
Spoiler for my answer
Just a response to your answer though...
Posted 21 March 2008 - 10:05 PM
how about ....Spoiler for slight correction
Posted 21 March 2008 - 10:22 PM
Posted 22 March 2008 - 01:34 AM
Posted 22 March 2008 - 01:39 AM
arrgh...This question is easy!Spoiler for easy answer
You need to re read the puzzle and amendment.You didn't get the puzzle at all. It states that if half opposes it, they die. So in your scenario the second would die. Also I doubt the first 3 would so easily let themselves be killed.
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