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40 replies to this topic

#11 Arjit Saraswat

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Posted 28 November 2011 - 04:09 PM

Hmm well I'm not sure how general this is, but this is how I found it.. (maybe the same way as you?)

Spoiler for method

the slaves with BC and DA can together open the door...
good effort though... think a bit more
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#12 Arjit Saraswat

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Posted 28 November 2011 - 04:13 PM

This is my solution...

Spoiler for The impossible riddle!!!

the 3 slaves cant open the door this way.......
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#13 Arjit Saraswat

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Posted 28 November 2011 - 04:34 PM

HINT : the answer is between 5 nd 10
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#14 tonyd

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Posted 28 November 2011 - 04:48 PM

This answer...
Spoiler for The impossible riddle!!!

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#15 curr3nt

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Posted 28 November 2011 - 04:53 PM

Spoiler for I get the same as tonyd

Edited by curr3nt, 28 November 2011 - 04:54 PM.

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#16 Arjit Saraswat

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Posted 28 November 2011 - 05:06 PM

This answer...

Spoiler for The impossible riddle!!!

congo..... you got it....
but tell me honestly.... did u do that yourself?
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#17 Arjit Saraswat

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Posted 28 November 2011 - 05:16 PM

you have done this with hit and trial......
can sum1 prove it generally with help of maths...
i am trying to use sets for this puzzle....
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#18 Anand Rahul

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Posted 28 November 2011 - 05:35 PM

From my interpretation of your problem, at least three slaves should be required to open the treasure. How are you going to distribute 3 keys among four slaves so any three will have a full set but no two will have a full set? If your answer is to give slaves 1, 2 and 3 a key each and not give any keys to slave 4, then you have changed the problem since slaves 4 with any other 2 could not open the treasure.

the questn doesnt says any 3 slave, it just says '3 of them worked together' not 'any three of them' as it was explicitly mentiond in case of wazir that he can open with any slave. i think that answers your question.
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#19 tonyd

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Posted 28 November 2011 - 05:51 PM

Mathematical explination
Spoiler for The impossible riddle!!!

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#20 Valic4

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Posted 28 November 2011 - 06:57 PM

Spoiler for Try this alternative

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