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#1
Posted 25 October 2011 - 07:22 PM
Sequence Q: 1, 8, 27, 64, q
Sequence R: 1/2, 2/3, 3/4, 4/5, r
Sequence S: 4, 9, 16, 25, s
Sequence T: 1, 3, 9, 27, t,
Sequence U: 3, 6, 7, −2, u
Where p,q,r,s,t and u are the 8th terms of each sequence
Find each.
#2
Posted 25 October 2011 - 07:36 PM
#3
Posted 25 October 2011 - 07:37 PM
u is what gets everyoneSpoiler for general answers
#4
Posted 25 October 2011 - 09:03 PM
Edited by David W, 25 October 2011 - 09:04 PM.
#5
Posted 25 October 2011 - 09:09 PM
Edited by curr3nt, 25 October 2011 - 09:13 PM.
#6
Posted 25 October 2011 - 09:10 PM
#7
Posted 25 October 2011 - 10:01 PM
@shakingdavid that's correct
#8
Posted 25 October 2011 - 11:13 PM
@curr3nt try again
@shakingdavid that's correct
Just because it isn't what you wanted doesn't mean it doesn't work.
#9
Posted 26 October 2011 - 08:11 AM
I wrote it down on my calculator so unless you wrote the equation wrong your answer is wrong. I tried it on the first 3 terms.
Just because it isn't what you wanted doesn't mean it doesn't work.
#10
Posted 26 October 2011 - 08:58 AM
I wrote it down on my calculator so unless you wrote the equation wrong your answer is wrong. I tried it on the first 3 terms.
Actually his equation is correct, but your calculator may be wrong. Be sure to make the calculations in the correct order: parentheses first, then powers, then multiplication and division, and finally addition/subtraction.
For n=1, we have n^3=n^2=n=1, so -(4/3)*1 + 7*1 - (26/3)*1 + 6 = -4/3 + 7 - 26/3 + 6 = -30/3 + 13 = -10 + 13 = 3
For n=2, we have n^3=8, n^2=4, so -(4/3)*8 + 7*4 - (26/3)*2 + 6 = -32/3 + 28 -52/3 + 6 = -84/3 + 34 = -28 + 34 = 6
For n=3, we have n^3=27, n^2=9, so -(4/3)*27 + 7*9 - (26/3)*3 + 6 = -108/3 + 63 - 78/3 + 6 = -186/3 + 69 = -62 + 69 = 7
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