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Cost of War

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#61 max0r4axor



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Posted 28 January 2010 - 07:36 PM

the answer is 10
70 eyes and 75 ears over lap the least amount by 45 which meas at least 45 had two injuries leaving 25 from the 70 and 30 from the 75 having one injury add together and get 55 that had one injury but since there's 80 arms to keeps this lowest takes those from the 55 and the remainder from the 45 leaving 55 plus the remainder of 45 - 25 = 20 now we have 20 + 55 = 75 having two injuries and 25 having 3 injuries now the final 85 legs take 85 legs from the 75 two injuries group giving them 3 injuries and the remainder is taken away from the 25 group resulting in 10 having 4 injuries and 15 + 75 = 90 only having 3 injuries
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#62 dark_magician_92


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Posted 09 January 2011 - 05:04 PM

not really sure why everyone is trying to use math for the answer....but..the obvious answer is 70!!! 70 is the smallest number of anything lost everything else had a higher number...!!

70 will be the answer if the question wud have asked the max. ppl who got 4 injuries, but we have been askd min. ppl.
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