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Posted 25 August 2008 - 02:05 AM
Two kids take the boat across
one kid gets out and the other kid goes back.
then the one kid gets out and the adult goes across
then, the adult gets out and the first kid gets back in and goes back
then both kids get in and cross.
voila the two kids and the adult are now across.
If there are two adults the same process would apply just a few more steps.
Posted 25 September 2008 - 09:38 PM
The sister will bring over the Mom and the brother to the other side (1 trip)
The sister will go back over to the other side (2 trips)
The sister will get the Fisherman and bring him over to the other side (3 trips)
The sister will go back to the other side (4 trips)
the sister will get the Father and bring him over to the other side (5 Trips)
There only 5 trips are needed and mabey six if the fisher leaving counts as a trip.
Posted 09 October 2008 - 04:37 AM
Posted 26 October 2008 - 02:25 PM
Pay attention to the original riddle, guys. It's not that hard.
Edited by IGOOGLELOVER, 26 October 2008 - 02:26 PM.
Posted 22 December 2008 - 10:54 PM
In a mathematical sense, there is NO solution, since the boat could not carry one children! The correct phrase would be "... or maximum two children."
Posted 12 October 2009 - 04:43 PM
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