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Humans and Monkeys


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37 replies to this topic

#21 dissatisfied

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Posted 29 December 2007 - 06:28 PM

I think that one big monkey, two small monkeys, and two humans initially approach a boat when they initiate this endeavor. Wouldn't that immediately put a stop to this problem since, before any thing gets on the boat the first time we're already dealing with a situation where we have 3 monkeys and 2 humans?
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#22 jbroseorg

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Posted 04 January 2008 - 02:20 PM

Another solution that requires the same 13 crossings is:
HHHMmm...
HHMm Hm>
HHMm HHH Mm> m
HHH HM HH> mm
HM Hm HM> Hm
Hm mm HH> HM
mm m Mm> HHH
m mM> mHHH
...mmMHHH
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#23 biodreamer

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Posted 09 January 2008 - 08:33 PM

Only big monkey and humans can row the boat and # of human has to be >= # of monkeys

HHHMmm
HHHm --> Mm
HHHm <-- M m
HHm --> MH m
HHm <-- M Hm <----- being eaten
Hm --> MH Hm
Hm <-- M HHm <----- being eaten
H --> Mm HHm <----- being eaten
H <-- M HHmm
--> MH HHmm
HHHMmm

I totally forgot the the last point where the monkey can jump out of the boat.

So it will have to be revised according to the solution.

Edited by biodreamer, 09 January 2008 - 08:42 PM.

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#24 Snowball

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Posted 29 January 2008 - 01:18 AM

what with all the h's and m's and >'s and <'s and .'s i just have one thing to say:

Hmmmmm>Hmmmmm<Hmmmm....???
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#25 dipti

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Posted 14 February 2008 - 11:58 PM

how about this:-

HHHMmm...
HHMm >Hm...
HHMm...Hm
HM >Hm...Hm <---who will bring back the boat
HM...HHmm
>HM...HHmm
...HHHMmm

sounds rite ??? :rolleyes:


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#26 jurmy2

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Posted 11 March 2008 - 06:35 PM

im not sure but heres what i think please correct me if im wrong but i thing the big monkey should row the little monkey across and then row back and oh nvm i dont know lol <_< *sigh* complicated much hummmmmm
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#27 ALFRED

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Posted 20 March 2008 - 06:39 PM

By saying the monkeys can jump out of the boat does that mean if the big monkey is paddling the boat he does not need to endanger the humans on shore when he drops one of the small monkeys off? That makes sense now that I spell it out. I love it when I answer my own questions.
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#28 Jarod997

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Posted 25 April 2008 - 04:13 PM

Actually, if you properly adhere to the puzzle requirements there is no apparent solution. Even the admin's solution violates the requirement "At all times, the number of humans on either side of the river must be greater or equal to the number of monkeys on that side". At any time, any side having only monkeys violates this rule since 0 Humans is not greater or equal to 1, 2 or 3 monkeys.

For the admin solution to be correct, the requirement would need to be revised to state "At all times, the number of humans must be greater or equal to the number of monkeys on any side of the river having both monkeys and humans".

Some would say having only monkeys on a given side would not result in a human being eaten by monkeys. That may sound reasonable, but the rule still exists that # Humans >= Monkeys "At all times ... on either side".

Chris


Actually, 0 >= 0 is true. In the beginning if there are zero humans on one side and zero monkeys, this condition holds.

I will attempt to word my solution as follows:

The large monkey "M" always rows the boat.
In each series of two transfers, the first takes a human, the second takes a small monkey.
*Note* There is no restriction on what can go in the boat
So then:
MH goes over, M comes back
Mm goes over, M comes back
MH goes over, M comes back
Mm goes over, M comes back
MH goes over, both get out

This assumes: M is always in the boat, and HM get in the boat and leave the boat (beginning and end) at the same time.

By keeping one monkey in the boat at all times we can always have one "surplus" human to move around without violating the human-monkey rule.

Comments?
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#29 jitHU

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Posted 27 April 2008 - 01:16 PM

no i guess not!!
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#30 Vishmi

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Posted 29 April 2008 - 08:35 AM

Good puzzle
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