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35 replies to this topic

#31 unreality

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Posted 02 March 2008 - 05:00 PM

Well I did figure out this:

(attached)

But I dont know if that helps

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  • square_diagonals2.jpg

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#32 heatherlovesjade

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Posted 03 March 2008 - 12:47 AM

there would be 10 meters to the non-mentioned post- seeing that its a square- its legnth times width for area right- so 30 x 30 would be 1800 km sq
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#33 heatherlovesjade

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Posted 03 March 2008 - 12:51 AM

not km just meters.
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#34 heatherlovesjade

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Posted 03 March 2008 - 12:51 AM

i think im wrong now.....
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#35 bonanova

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Posted 03 March 2008 - 05:21 AM

Well I did figure out this:

[diagram and equations]

But I dont know if that helps

Spoiler for You've got it. Now ...

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#36 unreality

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Posted 03 March 2008 - 10:57 PM

ah thanks, bonanova :D

b^2 + c^2 = s1^2 + s2^2 + s3^2 + s4^2

458 = s1^2 + s2^2 + s3^2 + s4^2

so now what? How do you solve for the s's? There could be a zillion answers, right? Or do you somehow use s1+s2=s3+s4 to help narrow it down? I'm still confused ;D
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