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#31 psafkow

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Posted 17 November 2007 - 05:01 PM

Where/when was it established that the sum of the ages had to be a unique solution?

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#32 Fioners

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Posted 19 November 2007 - 03:41 PM

love it
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#33 macmacdc

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Posted 13 December 2007 - 05:00 PM

The answer is 18, 2,1.
Only 18 year olds can drink.
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#34 mustavarest

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Posted 14 December 2007 - 04:15 PM

Hi - I've come into this one a bit late but I have read all the responses and I still am still unable to see anything in the question that suggests that the sum of the ages cannot be unique from the sum of any other possible combination of the ages. Can anyone out there please explain? My immediate thought was 2, 3 & 6 and I don't see why this, or any of the other combinations giving a product of 36, is not an acceptable solution.
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#35 rookie1ja

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Posted 14 December 2007 - 04:34 PM

Hi - I've come into this one a bit late but I have read all the responses and I still am still unable to see anything in the question that suggests that the sum of the ages cannot be unique from the sum of any other possible combination of the ages. Can anyone out there please explain? My immediate thought was 2, 3 & 6 and I don't see why this, or any of the other combinations giving a product of 36, is not an acceptable solution.


sum of the 3 numbers can not be unique ... so to use your "solution" ... 2+3+6=11 ... you can not split 11 into other 3 numbers that would make a product of 36, can you?
so if I knew that we drank 11 beers and the product was 36, then I would know the ages ... however, I did not know the ages (because we did not drink 11 beers)
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#36 tkktalks

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Posted 19 December 2007 - 10:02 PM

The answer could be 4,3,3 or 9,2,2. The Older son is wearing the red hat indicates that the other two children are of the same age or "twins". The sum of the beers if two people are taking at a time would be a even number and it can be 10 so 4,3,3 would be the answer to me.
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#37 ivyrose28288

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Posted 20 December 2007 - 12:58 AM

gees ole' granny of 9 here and I thought I was smarter than a 5th grader...oh well. When someone figures this out, PLEASE POST!, otherwise I will be awake all night ...
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#38 sloonark

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Posted 21 December 2007 - 01:54 AM

gees ole' granny of 9 here and I thought I was smarter than a 5th grader...oh well. When someone figures this out, PLEASE POST!, otherwise I will be awake all night ...



The answer is in the initial post. Click on the Spoiler for Solution bit.
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#39 Lemeshianos

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Posted 21 December 2007 - 10:51 AM

What if he has a baby that 0.5 years old?
:lol:
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#40 drek

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Posted 21 December 2007 - 11:02 PM

i say 6- 6- 1 and 9-2-2 are both right.
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