Consider the possibility that two of the children are 6, they're nearly identical twins but the slightly older one (a minute or two older) wears a red hat so that Peter can tell them apart. The third child is one. And Peter and Thomas have each drunk a 6-pack. So, 6 x 6 x 1 works.
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Children
Started by rookie1ja, Mar 30 2007 07:43 PM
62 replies to this topic
#11
Posted 26 June 2007 - 07:21 PM
#12
Posted 29 June 2007 - 12:28 AM
OK, so then it's 6-6-1?
6*6*1=36
6+6+1=13
And the oldest child wears a red hat to distinguish himself from his twin, no?
6*6*1=36
6+6+1=13
And the oldest child wears a red hat to distinguish himself from his twin, no?
#13
Posted 01 July 2007 - 04:50 PM
wat about the number of beers?
#14
Posted 11 July 2007 - 11:22 AM
True. The number of beers only work if you think of their ages logically and not being a couple of minutes different.
#15
Posted 15 July 2007 - 02:55 PM
I dont understand something,
If me and a sibling were both six what would stop one of us wearing a red hat and one of us wearing a different coloured hat or no hat at all?
If me and a sibling were both six what would stop one of us wearing a red hat and one of us wearing a different coloured hat or no hat at all?
#16
Posted 15 July 2007 - 06:48 PM
robadob:
In the riddle it says:
"OK, the last thing is that my oldest child wears a red hat."
Now, if you and your sibling were both 6, if your father said this, it doesn't make sense as there are two oldest children. This last statement points out that there is only one "oldest".
In the riddle it says:
"OK, the last thing is that my oldest child wears a red hat."
Now, if you and your sibling were both 6, if your father said this, it doesn't make sense as there are two oldest children. This last statement points out that there is only one "oldest".
#17
Posted 17 July 2007 - 09:49 PM
Answer must be 2 2 and 9
#18
Posted 24 July 2007 - 12:53 PM
Possible combinations for the age of the children are:
(4,3,3), (9,2,2), (9,4,1), (6,6,1), (12,3,1), (18,2,1), (36,1,1), (6,3,2)
Now, the hint is sum of the ages is being told and correct ages can't be guessed. So, the possible choices left are:
(9,2,2), (6,6,1).
Now, the hint is oldest is wearing a Red hat. So, the only answer left is:
(9,2,2)
which is our answer.
(4,3,3), (9,2,2), (9,4,1), (6,6,1), (12,3,1), (18,2,1), (36,1,1), (6,3,2)
Now, the hint is sum of the ages is being told and correct ages can't be guessed. So, the possible choices left are:
(9,2,2), (6,6,1).
Now, the hint is oldest is wearing a Red hat. So, the only answer left is:
(9,2,2)
which is our answer.
#19
Posted 01 August 2007 - 01:44 AM
It took me a sec, but I understand the need for the sum's to be unique. Without them being unique the last parameter would be obsolete or another would have to be there to replace it.
Great puzzle!
-Axilla
Great puzzle!
-Axilla
#20
Posted 09 August 2007 - 10:28 AM
"- The sum of their ages is exactly the number of beers we have drunk today.
- That is still not enough."
When Peter says "That is still not enough" in reply to Thomas's statement. He is assuming that a couple of them are twins(Which as profound as it may sound is just an assumption).
i still have my doubts for what made him conclude that they're twins, for, they don't have to be.
why cant they be a 9-4-1 or 2-3-6 or 4-3-3 (in case they are twins)?
- That is still not enough."
When Peter says "That is still not enough" in reply to Thomas's statement. He is assuming that a couple of them are twins(Which as profound as it may sound is just an assumption).
i still have my doubts for what made him conclude that they're twins, for, they don't have to be.
why cant they be a 9-4-1 or 2-3-6 or 4-3-3 (in case they are twins)?
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