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#1 HRAEDIUS

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Posted 22 February 2008 - 10:37 PM

Lets say that on a clock, y is the distance from the 12:00 to the minute hand (clockwise) and z is the distance from 12:00 to the hour hand. What time between 3-4 is y two times as much as z?
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#2 BeerGoddess

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Posted 23 February 2008 - 04:32 AM

Say the minute hand (Y) and the hour hand (Z) are both on 12:00. That would make Y=0 and Z=0, leaving the second hand to pass between 3 and 4 (it's not specified that the minute hand or the hour hand, themselves, had to be between 3 and 4). If Y=0 and Z=0, then 2(Y) also = 0, so 2(Y)=Z.

I guess that's kinda cheating, but it's all I got.
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#3 HRAEDIUS

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Posted 23 February 2008 - 06:47 AM

Say the minute hand (Y) and the hour hand (Z) are both on 12:00. That would make Y=0 and Z=0, leaving the second hand to pass between 3 and 4 (it's not specified that the minute hand or the hour hand, themselves, had to be between 3 and 4). If Y=0 and Z=0, then 2(Y) also = 0, so 2(Y)=Z.

I guess that's kinda cheating, but it's all I got.

I guess I was a bit unclear. The time has to be between 3:00 and 4:00

Spoiler for spoiler for hint

Edited by HRAEDIUS, 23 February 2008 - 06:51 AM.

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#4 brhan

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Posted 23 February 2008 - 02:32 PM

Spoiler for my solution

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#5 HRAEDIUS

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Posted 24 February 2008 - 08:33 AM

close but a bit off

Edited by HRAEDIUS, 24 February 2008 - 08:34 AM.

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#6 brhan

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Posted 24 February 2008 - 03:28 PM

I know where I made a mistake.

Spoiler for my solution


Hope this one makes sense.
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