me too. man i thought i had it.Clever. I initially thought of this 5 > 9, but there's not really a number there. 5 > x > 9 would be more appropriate I guess.
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#31
Posted 29 February 2008 - 05:01 PM
#32
Posted 29 February 2008 - 08:37 PM
#33
Posted 16 March 2008 - 10:46 PM
#34
Posted 02 May 2008 - 08:04 AM
Well, I tried the square-root operator, and it yielded an answer that was too big. So I figured, how about the third-root (Cube-root)? Still too big. So the fourth-root works, though. So putting the operator between the numbers would imply a multiplication operation, a two-in-one deal. The fourth-root of nine is approx. 1.372. Multiply that by five to get approx. 8.660, which is greater than five, and less than nine.
I agree with you
#35
Posted 03 June 2008 - 05:46 PM
You could also put a square root sign between them
No, because putting a square root between them would mean:
5 "times" the square root of nine, or 5x3, which is 15.
and 15 is not smaller than nine...but it was a nice try!
mikedotcom
#36
Posted 03 June 2008 - 05:51 PM
I agree with you
great thinking!
that means there is an infinite solution set:
5 nth root 9, where n>3
#37
Posted 10 June 2008 - 08:29 PM
#38
Posted 13 June 2008 - 05:14 AM
sorry, (5) squrt(9)You could also put a square root sign between them
(5) (3)
15
15 > 9
#39
Posted 27 June 2008 - 10:48 PM
#40
Posted 04 August 2008 - 06:43 PM
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