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Well, I tried the square-root operator, and it yielded an answer that was too big. So I figured, how about the third-root (Cube-root)? Still too big. So the fourth-root works, though. So putting the operator between the numbers would imply a multiplication operation, a two-in-one deal. The fourth-root of nine is approx. 1.372. Multiply that by five to get approx. 8.660, which is greater than five, and less than nine.
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42 replies to this topic
#22
Sereni-T
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Posted 02 January 2008 - 11:13 AM
You could put a 4th root sign. Which would yield the answer 8.66 
#23
spiralangell
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Posted 11 January 2008 - 07:44 AM
Ha, we just finished this stuff in math, 5<x>9 Wouldnt that be a number (x) that is bigger then 5 and less then 9?
#24
carafate
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Posted 13 January 2008 - 05:43 AM
i have a question tho, hw many people see the puzzle, solve it or look at the awncer then go away?
how many of them, if intrigued, bother to go to a second page?
I think reading the answers you all give is some of the best parts of this place. Y'all make me laugh when you argue.
#25
grottylittlewanker
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Posted 23 January 2008 - 08:06 PM
Thats what I was thinkingWell, I tried the square-root operator, and it yielded an answer that was too big. So I figured, how about the third-root (Cube-root)? Still too big. So the fourth-root works, though. So putting the operator between the numbers would imply a multiplication operation, a two-in-one deal. The fourth-root of nine is approx. 1.372. Multiply that by five to get approx. 8.660, which is greater than five, and less than nine.
#26
mudkip201
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Posted 03 February 2008 - 02:16 AM
No, this would not actually work. It would translate to five times the square root of nine. Since the square root of nine is three, the value would then be fifteen, which is not less than nine.
what if u wrote it this way: 5[[9]]
[9]=square root of nine
[[9]]=fourth root of nine
#27
mudkip201
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Posted 03 February 2008 - 02:16 AM
No, this would not actually work. It would translate to five times the square root of nine. Since the square root of nine is three, the value would then be fifteen, which is not less than nine.
what if u wrote it this way: 5[[9]]
[9]=square root of nine
[[9]]=fourth root of nine
#28
sweetie121184
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Posted 15 February 2008 - 08:55 PM
how about 5/9 division that gets you 5.5556
#29
rookie1ja
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Posted 15 February 2008 - 09:34 PM
5/9=0.55.. which is not between 5 and 9how about 5/9 division that gets you 5.5556
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#30
Cavazem
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Posted 26 February 2008 - 06:02 AM
Aren't digits just mathematical symbols that represent their corresponding numbers? So wouldn't the digits 6, 7, and 8 also be viable answers?
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