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Fraction


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29 replies to this topic

#11 stormpool

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Posted 05 July 2007 - 04:40 PM

Fraction - Back to the Number Puzzles
Can you use all 9 numerals - 1, 2, 3, 4, 5, 6, 7, 8 a 9 - above and below a fraction symbol in a random order, to create a fraction equalling 1/3 (one third)?



If you systematically choose which order to place the numbers in, then surely you cannot call it a 'random' order.

From this I deduce that Trial and error is the only way to solve this puzzle!
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#12 mannu

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Posted 09 July 2007 - 06:51 AM

How bout 1^9756482 / 3.

You never said not to use any mathematical operator..
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#13 ahem cuba

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Posted 22 July 2007 - 07:59 AM

3+6+9/(4+5)+18+27
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#14 awesselink

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Posted 06 August 2007 - 06:55 PM

Wow, thanks for the answer. I'd been trying to use 1-9 on the top AND bottom of the problem until i gave in and had a look at the solution. Could someone check for me and see if all nine on the top AND bottom is even able to be accomplished. As far as I can tell, it's not.



This is how I understood the question, and I found it's certainly possible. In fact, there are 768 occurrences of this. OK, I cheated and wrote a program to figure this out
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#15 icthy

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Posted 13 November 2007 - 02:07 AM

Hah. Oh.

I guess I misunderstood the problem, because this is what I came up with:

(1)(2+3)^0
(3)(4+5+6+7+8+9)^0

(which would of course reduce to

(1)(1)
(3)(1)

or

1
3

I guess that's the lazy answer.) (You could distrubute the numbers in the parentheses raised to 0 any way you want, anything raised to 0 is 1.)

edit:

How bout 1^9756482 / 3.

You never said not to use any mathematical operator..



Guess I wasn't the first person to come up with this ^^ I thought all the digits were supposed to be combined w/ operators, not as multi-digit number.
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#16 cbrowninnc

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Posted 31 December 2007 - 10:34 PM

Can you use all 9 numerals - 1, 2, 3, 4, 5, 6, 7, 8 a 9 - above and below a fraction symbol in a random order, to create a fraction equalling 1/3 (one third)?



Umm....by placing them in any set/given order would result in them no longer being placed randomly so I don't think it can be done. Unless of course the answer for any given combination of these numbers results in 1/3 which it does not.

Just a little nitpick at the wording ;-)
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#17 rookie1ja

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Posted 31 December 2007 - 10:41 PM


Can you use all 9 numerals - 1, 2, 3, 4, 5, 6, 7, 8 a 9 - above and below a fraction symbol in a random order, to create a fraction equalling 1/3 (one third)?



Umm....by placing them in any set/given order would result in them no longer being placed randomly so I don't think it can be done. Unless of course the answer for any given combination of these numbers results in 1/3 which it does not.

Just a little nitpick at the wording ;-)


I have noticed that as well ... too late
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#18 spiralangell

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Posted 11 January 2008 - 07:47 AM

So would this have more then one answer? or is it only one unique answer?
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#19 HelllxWeaver

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Posted 19 February 2008 - 11:27 PM

Also the top number has to all add up to a 3 digit number. good puzzle.
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#20 void28

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Posted 27 February 2008 - 01:50 AM

i dont think so. :huh: :huh:
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