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Fraction

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#1 rookie1ja

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Posted 30 March 2007 - 07:39 PM

Fraction - Back to the Number Puzzles
Can you arrange 9 numerals - 1, 2, 3, 4, 5, 6, 7, 8 and 9 - (using each numeral just once) above and below a division line, to create a fraction equaling to 1/3 (one third)?

This old topic is locked since it was answered many times. You can check solution in the Spoiler below.
Pls visit New Puzzles section to see always fresh brain teasers.

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#2 sn00bino

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Posted 27 April 2007 - 08:30 PM

I understand the solution. But how do you find it ? You can ' t test everything.
Sorry for my poor english
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#3 rookie1ja

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Posted 27 April 2007 - 09:23 PM

I understand the solution. But how do you find it ? You can ' t test everything.
Sorry for my poor english

A few hints:
1. first number must have 4 digits
2. second number must have 5 digits
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#4 sn00bino

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Posted 28 April 2007 - 10:40 AM

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#5 rookie1ja

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Posted 28 April 2007 - 10:54 AM

Because if you multiply a 4-digit number by 3, you can not get a number which is 30000 or bigger.
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#6 sn00bino

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Posted 28 April 2007 - 11:07 AM

ok thank you
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#7 lovruch

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Posted 02 May 2007 - 09:39 PM

numerator is 4 digit, denominator is 5 digit, 5 must be in numerator and only feasible place is the thousands place, hence denominator must start with 16 or 17,
denominator can't be 16*** because the ratio has to be 1/3 and only choices for hundreds place in numerator that are 4 and 6 will violate this condition or cause repetition, hence the number is 5***/17***, now hundreds place in num can be occupied only by 8 or 9, it can't be 9 or there will be repetition, so number is 58**/17***, now just simple hit and try on the ones and tens place of numerator will result in 5832/17496
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#8 fsm

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Posted 06 May 2007 - 01:05 AM

5823/17469 also works
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#9 robxmccarthy

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Posted 25 May 2007 - 05:07 PM

This one just about made my head explode. I took the same logical work down approach, but I couldn't get the last few numbers. I kept getting one repetition.
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#10 strikefiend

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Posted 20 June 2007 - 07:28 PM

Wow, thanks for the answer. I'd been trying to use 1-9 on the top AND bottom of the problem until i gave in and had a look at the solution. Could someone check for me and see if all nine on the top AND bottom is even able to be accomplished. As far as I can tell, it's not.
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