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9-digit Number


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18 replies to this topic

#11 rookie1ja

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Posted 04 December 2007 - 02:38 AM

Since you have an error in your conditions (the sum of the remaining numerals after 4 round-offs in your answer is NOT 24 as you stipulate--yours is 23) and with only 8 round-offs starting with rounding up, the last round-off has to be down, your answer is incorrect. I believe my answer is, therefore, equally valid. My 9-digit number is: 546372819
First rounding (up) yields: 546372820
2nd rounding (dn) yields: 546372800
3rd rounding (up) yields: 546373000
4th rounding (dn):546370000
5th rounding (up): 546400000
6th rounding (dn): 546000000
7th rounding (up): 550000000
8th rounding (dn): 500000000

Thanks for the challenge.
Linda, the Puzzlerz


as already mentioned above by savagegamer90 and Boiling Oil ... the sum of the remaining numerals after 4 round-offs is indeed 24
after 1st rounding - 473816950
after 2nd rounding - 473817000
after 3rd rounding - 473817000
after 4th rounding - 473820000

so 4+7+3+8+2=24
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#12 grottylittlewanker

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Posted 18 January 2008 - 03:31 AM

Since you have an error in your conditions (the sum of the remaining numerals after 4 round-offs in your answer is NOT 24 as you stipulate--yours is 23) and with only 8 round-offs starting with rounding up, the last round-off has to be down, your answer is incorrect. I believe my answer is, therefore, equally valid. My 9-digit number is: 546372819
First rounding (up) yields: 546372820
2nd rounding (dn) yields: 546372800
3rd rounding (up) yields: 546373000
4th rounding (dn):546370000
5th rounding (up): 546400000
6th rounding (dn): 546000000
7th rounding (up): 550000000
8th rounding (dn): 500000000

Thanks for the challenge.
Linda, the Puzzlerz


your answer isn't right because your number isn't commensurable by 6 or 7 ( i had to look it up, from what I read commensurable basically means divisible by) so the number was supposed to be divisible by 6 and 7, which the original answer is
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#13 mudkip201

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Posted 03 February 2008 - 02:31 AM

Since you have an error in your conditions (the sum of the remaining numerals after 4 round-offs in your answer is NOT 24 as you stipulate--yours is 23) and with only 8 round-offs starting with rounding up, the last round-off has to be down, your answer is incorrect. I believe my answer is, therefore, equally valid. My 9-digit number is: 546372819
First rounding (up) yields: 546372820
2nd rounding (dn) yields: 546372800
3rd rounding (up) yields: 546373000
4th rounding (dn):546370000
5th rounding (up): 546400000
6th rounding (dn): 546000000
7th rounding (up): 550000000
8th rounding (dn): 500000000

Thanks for the challenge.
Linda, the Puzzlerz


u r incorrect.
550000000 rounds to 600000000
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#14 mudkip201

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Posted 03 February 2008 - 02:31 AM

Since you have an error in your conditions (the sum of the remaining numerals after 4 round-offs in your answer is NOT 24 as you stipulate--yours is 23) and with only 8 round-offs starting with rounding up, the last round-off has to be down, your answer is incorrect. I believe my answer is, therefore, equally valid. My 9-digit number is: 546372819
First rounding (up) yields: 546372820
2nd rounding (dn) yields: 546372800
3rd rounding (up) yields: 546373000
4th rounding (dn):546370000
5th rounding (up): 546400000
6th rounding (dn): 546000000
7th rounding (up): 550000000
8th rounding (dn): 500000000

Thanks for the challenge.
Linda, the Puzzlerz


u r incorrect.
550000000 rounds to 600000000
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#15 fmegh

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Posted 15 February 2008 - 11:49 AM

My solution:

542673198

Chk it!

divisible by 6 & 8..
round off till end n u will get 500000000
also last 5 digits will add to 24 in the process...
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#16 rookie1ja

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Posted 15 February 2008 - 12:36 PM

My solution:

542673198

Chk it!

divisible by 6 & 8..
round off till end n u will get 500000000
also last 5 digits will add to 24 in the process...

542673198 is not divisible by 7 (as the puzzle requested)
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#17 sunshipballoons

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Posted 22 February 2008 - 06:39 PM

This is unsolveable. Round to what? The nearest multiple of 10? The nearest multiple of 5? The nearest multiple of 2?

Edited by sunshipballoons, 22 February 2008 - 06:40 PM.

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#18 rookie1ja

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Posted 22 February 2008 - 08:16 PM

This is unsolveable. Round to what? The nearest multiple of 10? The nearest multiple of 5? The nearest multiple of 2?

round to insanity :lol:
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#19 BrainBuster

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Posted 13 February 2010 - 08:23 AM

Since you have an error in your conditions (the sum of the remaining numerals after 4 round-offs in your answer is NOT 24 as you stipulate--yours is 23) and with only 8 round-offs starting with rounding up, the last round-off has to be down, your answer is incorrect. I believe my answer is, therefore, equally valid. My 9-digit number is: 546372819
First rounding (up) yields: 546372820
2nd rounding (dn) yields: 546372800
3rd rounding (up) yields: 546373000
4th rounding (dn): 546370000
5th rounding (up): 546400000
6th rounding (dn): 546000000
7th rounding (up): 550000000
8th rounding (dn): 500000000

Thanks for the challenge.
Linda, the Puzzlerz


The initial answer did look correct to me (I think the description of alternate rounding, wasn't meant to say it HAS to round up first, rather it was a specifc example presented to illustrate what was meant by alternate rounding).

There are a few issues with the alternative solution you presented:

Your sum after 4 rounds of rounding equals 25

Also, your final round down, should have been a round up (given that the 5 dictates a round-up)

Last but not least, your intial number is not divisible by 7 nor 6
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