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### #1

Posted 18 February 2008 - 04:47 AM

### #2

Posted 18 February 2008 - 09:53 AM

### #3

Posted 18 February 2008 - 09:58 AM

Nope!Spoiler for a guess

89. Detailed solution would come later!

### #4

Posted 20 February 2008 - 09:43 AM

### #5

Posted 22 February 2008 - 09:57 AM

It feels like the Fibonacci Series but it will take too long to explain how.

So i'll stick to my intuition.

1 1 2 3 5 8 13 21 34 55

**89**

The 11th number in the sequence!

### #6

Posted 22 February 2008 - 10:08 AM

Yup .. the sequence is Fibonacci series but why did you choose 89 as ur answer?!Interesting...

It feels like the Fibonacci Series but it will take too long to explain how.

So i'll stick to my intuition.

1 1 2 3 5 8 13 21 34 5589

The 11th number in the sequence!

### #7

Posted 22 February 2008 - 11:27 AM

Yup .. the sequence is Fibonacci series but why did you choose 89 as ur answer?!

Well I simply started with the second 1 in the series with the first brick (1 possible answer)

The 2 bricks got me 2 easy...

3 got me 5 a little more complicated

so for 10 bricks 11th number not 10th!

This is because length = 2X width...

### #8

Posted 22 February 2008 - 01:55 PM

How can we still use the same sequence? (if possible)

Of course we consider the wall to be 30x120 cm

**Edited by roolstar, 22 February 2008 - 01:58 PM.**

### #9

Posted 22 February 2008 - 05:11 PM

Umm it would be an offshoot of another Fibonacci I think.Now what if the bricks were 30x10x10??

How can we still use the same sequence? (if possible)

Of course we consider the wall to be 30x120 cm

The problem will become more interesting if I would say that you have to make a 40x150x10 wall using minimum number of 20x10x10 brick. What are the no. of patterns? What are the no. of patterns for general case of this?

### #10

Posted 22 February 2008 - 05:19 PM

Roolstar .. Actually 3 should have got you 3 only! 4 bricks would be needed t make 5 patterns .. but I figure, you got the point..Well I simply started with the second 1 in the series with the first brick (1 possible answer)

The 2 bricks got me 2 easy...

3 got me 5 a little more complicated

so for 10 bricks 11th number not 10th!

This is because length = 2X width...

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