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#11 unreality

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Posted 18 February 2008 - 04:54 PM

Storm and Bonanova got it :D

MysteryKidakah, try writing out the five letters and looking at the probabilities for all three. I'll give you a hint: the winning probability for the right answer is 1/4, or 0.25, for all three combinations

btw bonanova is wrong about jkyle's followup question's answers- nobody can be played twice in a row. Making a 1/1 chance impossible for any of the three combos.

Here's a follow-up question:

Spoiler for follow up question

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#12 Jkyle1980

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Posted 19 February 2008 - 12:17 AM

Storm and Bonanova got it :D

MysteryKidakah, try writing out the five letters and looking at the probabilities for all three. I'll give you a hint: the winning probability for the right answer is 1/4, or 0.25, for all three combinations

btw bonanova is wrong about jkyle's followup question's answers- nobody can be played twice in a row. Making a 1/1 chance impossible for any of the three combos.

Here's a follow-up question:

Spoiler for follow up question


From the numbers, I would say that the option that gives you two 50% chances is the best. However, I never got that far in statistics and want to know how you figure odds that add up to 9/8 or over 100%. The same with rolling a die 6 times. The odds of getting any number add up to 100%, but I know this isn't true.
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#13 unreality

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Posted 19 February 2008 - 12:34 AM

Yeah me too... I think it just means HIGHLY LIKELY... but out of 8 dice rolls, how can you get 9 sixes? etc. It's confuding... like when something has a 200% chance of happening... wtf? lol. I never said I knew the answer to my follow up questions hehe. Though I'm with you in that the 1/2, 1/2, 1/8 is better than the 1/4, 1/4, 1/4
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#14 unreality

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Posted 23 August 2008 - 07:44 PM

btw, about rolling 6 six-sided die and seeing what your chances are of getting a six, look at the probability of NOT getting a 6. Ie, the probably of getting at least one six after 6 rolls is:

p = 1 - ((5/6)^6)

or add up all the numbers in the binomial distribution except the last one in the line
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#15 itsclueless

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Posted 23 August 2008 - 08:55 PM

Yeah me too... I think it just means HIGHLY LIKELY... but out of 8 dice rolls, how can you get 9 sixes? etc. It's confuding... like when something has a 200% chance of happening... wtf? lol. I never said I knew the answer to my follow up questions hehe. Though I'm with you in that the 1/2, 1/2, 1/8 is better than the 1/4, 1/4, 1/4



btw, about rolling 6 six-sided die and seeing what your chances are of getting a six, look at the probability of NOT getting a 6. Ie, the probably of getting at least one six after 6 rolls is:

p = 1 - ((5/6)^6)

or add up all the numbers in the binomial distribution except the last one in the line


Actually, the first case is exactly like the second. Your chances of winning when all three are playing are not 1/4 + 1/4 + 1/4, they are 1 - (3/4)^3 = 0.578125. Same thing with the other setup: 1 - (1/2)*(1/2)*(7/8) = 0.78125. Two 1/2 chances and one 1/8 chance are significantly better odds for you.
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