Welcome to BrainDen.com - Brain Teasers Forum
|Welcome to BrainDen.com - Brain Teasers Forum. Like most online communities you must register to post in our community, but don't worry this is a simple free process. To be a part of BrainDen Forums you may create a new account or sign in if you already have an account.
As a member you could start new topics, reply to others, subscribe to topics/forums to get automatic updates, get your own profile and make new friends.
Of course, you can also enjoy our collection of amazing optical illusions and cool math games.
If you like our site, you may support us by simply clicking Google "+1" or Facebook "Like" buttons at the top.
If you have a website, we would appreciate a little link to BrainDen.
Thanks and enjoy the Den :-)
Posted 17 February 2008 - 12:26 AM
A good thing (for you) is that you can beat the Prince every single time you play him, no matter what. Yeah, he's that bad. You have a 1/2 chance to beat his mother, the Queen, and only a 1/4 chance to beat the King.
The King comes to your cell with the challenge: you will play 5 games of zarball against the royal family (which is the King, Queen and Prince). You can play them in any order you so choose, though none of the family members can play more than twice total, and none of them can play twice in a row either.
If you win the first, fourth and fifth game, you will go free.
If you win both the second and third game, you will go free.
If you win both the third and fourth game, you will go free.
(You could get two of those combinations, or even all three, and still go free. You just have to succeed at one of those combinations)
Maybe it's not the best choice probability-wise, but you don't want to put a higher chance in any of the three combinations, to put more eggs in one basket, so to speak. You want your chances to be equal for all three. So how should you have the King arrange the games if you want the highest equal chance for all three combinations for going free? (ie, an example would be to have a 1/16 chance to win games 1,4 and 5, a 1/16 chance to win games 2 and 3, and a 1/16 chance to win games 3 and 4... though I can tell you right now 1/16 isn't the highest possible)
Posted 17 February 2008 - 01:20 AM
2 and 3- kpqpq
3 and 4- kqpqp
somebody else will probably figure out the actual probabilitys and the right answers but quickly looking at it this is what i would do
Posted 17 February 2008 - 03:34 AM
However, by using JKQJQ, you increase your odds of being release through the 1st and 3rd situations to 1/2 without affecting your odds of the 2nd situation. This is the order I would use.
Posted 17 February 2008 - 03:48 PM
And to whoever changed the topic title, thanks! (though I meant "Five Games of Zarball" instead of "Four Games of Zarball", Just "Five" is fine too lol )
Posted 17 February 2008 - 06:07 PM
i was just doin one choice for each way to get free
i guess i didnt really understand the question
i get it now that i saw the answer
if you have anymore of these you should post them, there fun
Posted 17 February 2008 - 07:14 PM
Posted 18 February 2008 - 04:43 AM
Play the Prince twice - either of the two-game matches.
Take the question a different way. Which combination gives you the best overall odds of winning one of the three?
Vidi vici veni.
0 user(s) are reading this topic
0 members, 0 guests, 0 anonymous users