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Posted 28 December 2009 - 01:05 AM
Posted 29 December 2009 - 10:38 AM
Posted 29 December 2009 - 12:46 PM
Spoiler for dont wait next digit but maybe next solution
I am fairly certain that this will be solvable. This was set as a problem for University Engineering students who were assured that there was a working answer
If you re-read the messages at the beginning , you will find a link to earlier Codebreaker puzzles from the same source. At one stage, like you , I thought that these earlier puzzles were "unsolvable" ...but some of the more industrious members on this forum found working solutions . Take a look and see if you can understand the answers found.A couple of the methods used are quite ingenious
So for this one , then as we are finding , it won`t be easy, but there will be a working answer.
I prefer puzzles like this where you can spend a lot of time trying to work them out.It can certainly be more frustrating than Sudoku , but once a solution is found , then the achievement felt is a lot higher .
( During World War 2 , at Bletchley Park , they had no choice but to keep trying to crack the codes so I like to think the same about this one.!)
Don`t forget that I`m offering prizes for working solutions.
Posted 31 December 2009 - 01:35 AM
Read through them and see what you think
Edited by redrooster, 31 December 2009 - 01:39 AM.
Posted 05 January 2010 - 12:10 AM
Edited by Medji, 05 January 2010 - 12:12 AM.
Posted 06 January 2010 - 12:51 AM
I have a theory:Spoiler for
I can see the logic in your theory and agree that it is has potential (I have also pursued a similar line of thought with various calculations...but no success yet !)
Can I just make a couple of additional , general comments.
1....C2 may NOT be the next digit to be decoded. It might by C3 or C4 before C2
2...There may be some form of "carry over" from the calculation for a previous code digit.
Example : if the calculation that produced C1 was a number higher than 10 .... eg 12 ....then the 1 (the "tens" )could possibly be "carried over" and used in a calculation for C2 or C3 or C4 .......This has happened in previous Codebreaker problems and can explain why a theory may work for most of the time, but has a few exceptions.....and these exceptions may be 1 (or 2 etc. ) higher or lower than the result from the main theory. The difference being a "carry over " from the preceding calculation.
Posted 13 January 2010 - 12:28 PM
Here are my thoughts.Spoiler for
Welcome back toxicoxyde..I was hoping that you would take a look at this problem. It is a lot harder than that last one in Aug 2008....and I found some of that rather difficult at the time ...or at least until someone pointed out the multiple of 7 idea and the remainder solution to some of the code digits.
I can follow all your reasoning ( and it is interesting that a formula can be created to solve C1 )
I have now spent a fair bit of time on this problem and just cannot see a common point for C2 C3 or C4.
As I pointed out earlier, I am convinced that B1+B2+B3+B4 are all involved in the next stage......but what that is has not been realised yet.
Is anyone else working on any theories that they would like to share?
Perhaps we ought to have a " brainstorming" session for a bit of lateral thinking.
Posted 21 January 2010 - 10:49 AM
Spoiler for an observation
An interesting observation.
All we need now is to see how they are related mathematically.
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